If $5.85 \ g$ of $NaCl$ (molecular weight $58.5$) is dissolved in water and the solution is made up to $0.5 \ L$,the molarity of the solution will be (in $M$)

Commercially available $H_2SO_4$ is $98 \ g$ by weight of $H_2SO_4$ and $2 \ g$ by weight of water. Its density is $1.38 \ g \ cm^{-3}$. Calculate the molality $(m)$ of $H_2SO_4$ (molar mass of $H_2SO_4$ is $98 \ g \ mol^{-1}$). (in $m$)

The molality and molarity of a solution of glucose in water which is labelled as $10 \% (w/w)$ are respectively (density of solution $= 1.2 \ g \ mL^{-1}$)

Define mole fraction.

$A$ $2.0 \, M$ solution is obtained when $0.5 \, mole$ of solute is dissolved in:

If $2 \ g$ of $NaOH$ is dissolved to make $200 \ mL$ solution at $25^{\circ} C$, the molarity $(M)$ at $90^{\circ} C$ is