If sec theta + tan theta = p, (p neq 0),then | vedclass

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(B) Given: $\sec 	heta + 	an 	heta = p$ ......... $(1)$We know the identity: $\sec^2 	heta - 	an^2 	heta = 1$This can be factored as: $(\sec 	h

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$\frac{1}{2}(p + 1/p), p 
eq 0$

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(B) Given: $\sec 	heta + 	an 	heta = p$ ......... $(1)$We know the identity: $\sec^2 	heta - 	an^2 	heta = 1$This can be factored as: $(\sec 	heta + 	an 	heta)(\sec 	heta - 	an 	heta) = 1$Substituting $(1)$ into the identity: $p(\sec 	heta - 	an 	heta) = 1$Therefore: $\sec 	heta - 	an 	heta = \frac{1}{p}$ ......... $(2)$Adding equation $(1)$ and equation $(2)$:$(\sec 	heta + 	an 	heta) + (\sec 	heta - 	an 	heta) = p + \frac{1}{p}$$2 \sec 	heta = p + \frac{1}{p}$$\sec 	heta = \frac{1}{2}(p + \frac{1}{p})$

If $\sec \theta + \tan \theta = p, (p \neq 0)$,then $\sec \theta$ is equal to:

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