If 3 sin theta + 5 cos theta = 5,then the val | vedclass

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(A) Given equations are:$3 \sin 	heta + 5 \cos 	heta = 5$ ..... $(1)$$5 \sin 	heta - 3 \cos 	heta = x$ ..... $(2)$Squaring both equations and addi

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$\pm 3$

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(A) Given equations are:$3 \sin 	heta + 5 \cos 	heta = 5$ ..... $(1)$$5 \sin 	heta - 3 \cos 	heta = x$ ..... $(2)$Squaring both equations and adding them:$(3 \sin 	heta + 5 \cos 	heta)^2 + (5 \sin 	heta - 3 \cos 	heta)^2 = 5^2 + x^2$$(9 \sin^2 	heta + 25 \cos^2 	heta + 30 \sin 	heta \cos 	heta) + (25 \sin^2 	heta + 9 \cos^2 	heta - 30 \sin 	heta \cos 	heta) = 25 + x^2$$(9 + 25) \sin^2 	heta + (25 + 9) \cos^2 	heta = 25 + x^2$$34(\sin^2 	heta + \cos^2 	heta) = 25 + x^2$Since $\sin^2 	heta + \cos^2 	heta = 1$,we have:$34 = 25 + x^2$$x^2 = 34 - 25 = 9$$x = \pm 3$

If $3 \sin \theta + 5 \cos \theta = 5$,then the value of $5 \sin \theta - 3 \cos \theta$ will be

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