If a-b=1 and ab=6,then what is the value of ( | vedclass

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(C) We are given the equations $a-b=1$ and $ab=6$.We use the algebraic identity for the difference of cubes: $a^3-b^3 = (a-b)^3 + 3ab(a-b)$.Substitute

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$19$

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(C) We are given the equations $a-b=1$ and $ab=6$.We use the algebraic identity for the difference of cubes: $a^3-b^3 = (a-b)^3 + 3ab(a-b)$.Substitute the given values into the identity:$a^3-b^3 = (1)^3 + 3(6)(1)$.Calculate the result:$a^3-b^3 = 1 + 18 = 19$.Therefore,the value of $(a^3-b^3)$ is $19$.

If $a-b=1$ and $ab=6$,then what is the value of $(a^3-b^3)$?

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