If log x : 3 = log y : 4 = log z : 5,then zx | vedclass

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(B) Given that $\frac{\log x}{3} = \frac{\log y}{4} = \frac{\log z}{5} = k$.From this,we can express the logarithms as:$\log x = 3k$,$\log y = 4k$,and

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$y^2$

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(B) Given that $\frac{\log x}{3} = \frac{\log y}{4} = \frac{\log z}{5} = k$.From this,we can express the logarithms as:$\log x = 3k$,$\log y = 4k$,and $\log z = 5k$.We want to find the value of $zx$. Using the properties of logarithms,we have:$\log(zx) = \log z + \log x$.Substituting the values in terms of $k$:$\log(zx) = 5k + 3k = 8k$.Since $\log y = 4k$,we can write $8k = 2(4k) = 2 \log y$.Using the power rule of logarithms,$2 \log y = \log(y^2)$.Therefore,$\log(zx) = \log(y^2)$,which implies $zx = y^2$.

If $\log x : 3 = \log y : 4 = \log z : 5$,then $zx =$

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