(D) The nuclear reaction is given by: $_{92}U^{235} + _{0}n^{1} \to _{54}Xe^{139} + _{38}Sr^{94} + x(_{0}n^{1})$.Applying the law of conservation of m

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(D) The nuclear reaction is given by: $_{92}U^{235} + _{0}n^{1} \to _{54}Xe^{139} + _{38}Sr^{94} + x(_{0}n^{1})$.Applying the law of conservation of mass number: $235 + 1 = 139 + 94 + x$.$236 = 233 + x$.$x = 3$.Therefore,the product $X$ is $3$ neutrons.

Class 12 Chemistry Nuclear Chemistry Artificial transmutation

Medium

If $_{92}U^{235}$ nucleus absorbs a neutron and disintegrates into $_{54}Xe^{139}$,$_{38}Sr^{94}$ and $X$,then what will be the product $X$?

A
$\alpha$-particle
B
$\beta$-particle
C
$2$ neutrons
D
$3$ neutrons

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Class 12

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Nuclear Chemistry

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Artificial transmutation

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EasyWBJEE 2014

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DifficultIIT 2013

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Medium

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Which one of the following nuclear transformations is of the $(n, p)$ type?

MediumAIIMS 1983

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If $_{92}U^{235}$ nucleus absorbs a neutron and disintegrates into $_{54}Xe^{139}$,$_{38}Sr^{94}$ and $X$,then what will be the product $X$?

Similar Questions

According to the nuclear reaction $_4Be + _2He^4 \to _6C^{12} + _0n^1$,what is the mass number of the $Be$ atom?

$_{98}Cf^{246}$ was formed along with a neutron when an unknown radioactive substance was bombarded with $_{6}C^{12}$. The unknown substance was:

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