If sqrt{3} tan theta = 1,then find the value | vedclass

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(C) Given that,$\sqrt{3} 	an 	heta = 1$.$	an 	heta = \frac{1}{\sqrt{3}}$.Since $	an 30^{\circ} = \frac{1}{\sqrt{3}}$,we have $	heta = 30^{\circ}

Vedclass · Accepted Answer

$-\frac{1}{2}$

Vedclass · Answer

(C) Given that,$\sqrt{3} 	an 	heta = 1$.$	an 	heta = \frac{1}{\sqrt{3}}$.Since $	an 30^{\circ} = \frac{1}{\sqrt{3}}$,we have $	heta = 30^{\circ}$.Now,substitute $	heta = 30^{\circ}$ into the expression $\sin^{2} 	heta - \cos^{2} 	heta$:$\sin^{2} 30^{\circ} - \cos^{2} 30^{\circ} = \left(\frac{1}{2}ight)^{2} - \left(\frac{\sqrt{3}}{2}ight)^{2}$.$= \frac{1}{4} - \frac{3}{4}$.$= \frac{1 - 3}{4} = -\frac{2}{4} = -\frac{1}{2}$.

If $\sqrt{3} \tan \theta = 1$,then find the value of $\sin^{2} \theta - \cos^{2} \theta$.

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