If tan 7 theta cdot tan 3 theta = 1, then the | vedclass

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(D) Given equation: $	an 7 	heta \cdot 	an 3 	heta = 1$We know that $	an 3 	heta = \frac{1}{\cot 3 	heta}$,so $	an 7 	heta = \frac{1}{	an 3

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$9$

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(D) Given equation: $	an 7 	heta \cdot 	an 3 	heta = 1$We know that $	an 3 	heta = \frac{1}{\cot 3 	heta}$,so $	an 7 	heta = \frac{1}{	an 3 	heta} = \cot 3 	heta$.Using the trigonometric identity $\cot \alpha = 	an(90^{\circ} - \alpha)$,we can write:$	an 7 	heta = 	an(90^{\circ} - 3 	heta)$Equating the angles:$7 	heta = 90^{\circ} - 3 	heta$Adding $3 	heta$ to both sides:$10 	heta = 90^{\circ}$Dividing by $10$:$	heta = 9^{\circ}$

If $\tan 7 \theta \cdot \tan 3 \theta = 1,$ then the value of $\theta$ is ..........

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