The value of tan 5^{circ} cdot tan 25^{circ} | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given expression: $	an 5^{\circ} \cdot 	an 25^{\circ} \cdot 	an 45^{\circ} \cdot 	an 65^{\circ} \cdot 	an 85^{\circ}$We know that $	an 45^{\

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(C) Given expression: $	an 5^{\circ} \cdot 	an 25^{\circ} \cdot 	an 45^{\circ} \cdot 	an 65^{\circ} \cdot 	an 85^{\circ}$We know that $	an 45^{\circ} = 1$ and $	an(90^{\circ} - 	heta) = \cot 	heta$.Substituting these values:$= 	an 5^{\circ} \cdot 	an 25^{\circ} \cdot 1 \cdot 	an(90^{\circ} - 25^{\circ}) \cdot 	an(90^{\circ} - 5^{\circ})$$= 	an 5^{\circ} \cdot 	an 25^{\circ} \cdot 1 \cdot \cot 25^{\circ} \cdot \cot 5^{\circ}$Since $	an 	heta \cdot \cot 	heta = 1$,we group the terms:$= (	an 5^{\circ} \cdot \cot 5^{\circ}) \cdot (	an 25^{\circ} \cdot \cot 25^{\circ}) \cdot 1$$= 1 \cdot 1 \cdot 1 = 1$

The value of $\tan 5^{\circ} \cdot \tan 25^{\circ} \cdot \tan 45^{\circ} \cdot \tan 65^{\circ} \cdot \tan 85^{\circ}$ is $\ldots \ldots \ldots \ldots .$.

Similar Questions

$\tan ^{2} \theta - \sec ^{2} \theta = \ldots \ldots \ldots$

$\frac{1}{\cos ^{2} \theta}-\frac{1}{\cot ^{2} \theta} = \dots$

$\operatorname{cosec} 40^{\circ} = \ldots \ldots \ldots \ldots$

In $\Delta ABC$,$m \angle C = 90^{\circ}$ and $\cos B = \frac{1}{2}$,then $\operatorname{cosec} A = \ldots$

Prove that,
$\frac{\sin \theta}{1+\cos \theta}+\frac{1+\cos \theta}{\sin \theta}=2 \operatorname{cosec} \theta$

Vedclass Test Series

Exam Paper Generator

Online Exam Module