If 2 sin^{2} theta - cos^{2} theta = 2,then f | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given equation: $2 \sin^{2} 	heta - \cos^{2} 	heta = 2$Using the identity $\cos^{2} 	heta = 1 - \sin^{2} 	heta$,we substitute it into the equa

Vedclass · Accepted Answer

$90$

Vedclass · Answer

(B) Given equation: $2 \sin^{2} 	heta - \cos^{2} 	heta = 2$Using the identity $\cos^{2} 	heta = 1 - \sin^{2} 	heta$,we substitute it into the equation:$2 \sin^{2} 	heta - (1 - \sin^{2} 	heta) = 2$Simplify the expression:$2 \sin^{2} 	heta - 1 + \sin^{2} 	heta = 2$$3 \sin^{2} 	heta - 1 = 2$Add $1$ to both sides:$3 \sin^{2} 	heta = 3$Divide by $3$:$\sin^{2} 	heta = 1$Taking the square root:$\sin 	heta = 1$ (considering the principal value)Since $\sin 90^{\circ} = 1$,we have:$	heta = 90^{\circ}$

If $2 \sin^{2} \theta - \cos^{2} \theta = 2$,then find the value of $\theta$. (in $^{\circ}$)

Similar Questions

$\frac{1}{\cos ^{2} \theta}-1 = \ldots$

If $\sin 5 \theta = \cos 5 \theta$,then the value of $\theta$ is ..........

$(1-\cos \theta)(1+\cos \theta) = \dots$

State whether the following is 'True' or 'False' and justify your answer:
If $\cos A + \cos^2 A = 1$,then $\sin^2 A + \sin^4 A = 1$.

$\tan 23^{\circ} \tan 42^{\circ} \tan 48^{\circ} \tan 67^{\circ} = \ldots \ldots \ldots \ldots .$

Vedclass Test Series

Exam Paper Generator

Online Exam Module