If 0.5 , A current is passed through an acidi | vedclass

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(B) According to Faraday's first law of electrolysis,the mass of substance deposited $(W)$ is given by the formula: $W = \frac{E \cdot I \cdot t}{9650

Vedclass · Accepted Answer

$0.336$

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(B) According to Faraday's first law of electrolysis,the mass of substance deposited $(W)$ is given by the formula: $W = \frac{E \cdot I \cdot t}{96500}$.Here,$E = 108 \, g/eq$,$I = 0.5 \, A$,and $t = 10 	imes 60 = 600 \, s$.Substituting the values: $W = \frac{108 	imes 0.5 	imes 600}{96500}$.$W = \frac{32400}{96500} \approx 0.3357 \, g$.Rounding to three decimal places,we get $0.336 \, g$.

If $0.5 \, A$ current is passed through an acidified silver nitrate solution for $10 \, min$,the mass of silver deposited on the cathode is ........... $g$ (equivalent weight of silver $= 108$).

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