If frac{3}{x}-frac{2}{y}=5 and frac{4}{x}-fra | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Let $u = \frac{1}{x}$ and $v = \frac{1}{y}$.The given equations become:$3u - 2v = 5$  --- $(1)$$4u - 5v = 2$  --- $(2)$To solve for $u$ and $v$,mu

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) Let $u = \frac{1}{x}$ and $v = \frac{1}{y}$.The given equations become:$3u - 2v = 5$  --- $(1)$$4u - 5v = 2$  --- $(2)$To solve for $u$ and $v$,multiply $(1)$ by $5$ and $(2)$ by $2$:$15u - 10v = 25$  --- $(3)$$8u - 10v = 4$  --- $(4)$Subtract $(4)$ from $(3)$:$(15u - 8u) = 25 - 4$$7u = 21 \implies u = 3$Substitute $u = 3$ into $(1)$:$3(3) - 2v = 5$$9 - 2v = 5$$-2v = -4 \implies v = 2$Thus,$\frac{1}{x} = 3$ and $\frac{1}{y} = 2$.The value of $\frac{1}{x} - \frac{1}{y} = 3 - 2 = 1$.

If $\frac{3}{x}-\frac{2}{y}=5$ and $\frac{4}{x}-\frac{5}{y}=2,$ then the value of $\frac{1}{x}-\frac{1}{y}$ is ............ $(x, y \neq 0)$

Similar Questions

The ages of two girls are in the ratio $5:7$. Eight years ago,their ages were in the ratio $7:13$. Represent this situation as a pair of linear equations in two variables.

$x$ is larger in two numbers $x$ and $y$. Two times the larger number is $4$ more than five times the smaller number. The equation form of this data is $\ldots \ldots \ldots \ldots$

Solve the following pair of linear equations by the method of substitution: $x + 8y = 19$ and $2x + 11y = 28$.

One equation of a pair of dependent linear equations is $-5x + 7y = 2$. The second equation can be

After $x$ years,the sum of the ages of Sachin and Sehwag will be $y$ years,then the sum of the ages before $3$ years was $\ldots \ldots \ldots \ldots$ years.

Vedclass Test Series

Exam Paper Generator

Online Exam Module