If Delta ABC cong Delta RPQ and the perimeter | vedclass

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(A) Given that $\Delta ABC \cong \Delta RPQ$.By the property of congruent triangles,corresponding parts of congruent triangles are equal $(CPCT)$.This

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$18$

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(A) Given that $\Delta ABC \cong \Delta RPQ$.By the property of congruent triangles,corresponding parts of congruent triangles are equal $(CPCT)$.This implies that the sides of $\Delta ABC$ are equal to the corresponding sides of $\Delta RPQ$.Specifically,$AB = RP$,$BC = PQ$,and $AC = RQ$.The perimeter of a triangle is the sum of its three sides.Perimeter of $\Delta ABC = AB + BC + AC = 18 \, cm$.Since $\Delta ABC \cong \Delta RPQ$,the perimeter of $\Delta RPQ$ is equal to the perimeter of $\Delta ABC$.Perimeter of $\Delta RPQ = RP + PQ + RQ = AB + BC + AC = 18 \, cm$.Note that the perimeter of $\Delta PQR$ is the same as the perimeter of $\Delta RPQ$ because the set of side lengths is identical.Therefore,the perimeter of $\Delta PQR$ is $18 \, cm$.

If $\Delta ABC \cong \Delta RPQ$ and the perimeter of $\Delta ABC$ is $18 \, cm$,then the perimeter of $\Delta PQR$ is $cm$.

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