If $n$ is the smallest natural number such that $n+2n+3n+\ldots+99n$ is a perfect square,then the number of digits of $n^2$ is

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    more than $3$

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Let $\{a_{n}\}_{n=1}^{\infty}$ be a sequence such that $a_{1}=1, a_{2}=1$ and $a_{n+2}=2a_{n+1}+a_{n}$ for all $n \geq 1$. Then the value of $47 \sum_{n=1}^{\infty} \frac{a_{n}}{2^{3n}}$ is equal to $.....$

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$1.$ Which of the following is correct?
$(A)$ $a_{17} = a_{16} + a_{15}$
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$(A)$ $7$ $(B)$ $8$ $(C)$ $9$ $(D)$ $11$
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