If $x+\frac{1}{x}=a$ and $x^2+\frac{1}{x^3}=b$,then $x^3+\frac{1}{x^2}$ is

  • A
    $a^3+a^2-3a-2-b$
  • B
    $a^3-a^2-3a+4-b$
  • C
    $a^3-a^2+3a-6-b$
  • D
    $a^3+a^2+3a-16-b$

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