If vec{A} + vec{B} + vec{C} = 0,then vec{A} t | vedclass

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(B) Given the equation $\vec{A} + \vec{B} + \vec{C} = 0$.We can write $\vec{A} = -(\vec{B} + \vec{C})$.Taking the cross product of both sides with $\v

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$\vec{B} 	imes \vec{C}$

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(B) Given the equation $\vec{A} + \vec{B} + \vec{C} = 0$.We can write $\vec{A} = -(\vec{B} + \vec{C})$.Taking the cross product of both sides with $\vec{B}$:$\vec{A} 	imes \vec{B} = -(\vec{B} + \vec{C}) 	imes \vec{B}$.Using the distributive property of the cross product:$\vec{A} 	imes \vec{B} = -(\vec{B} 	imes \vec{B}) - (\vec{C} 	imes \vec{B})$.Since the cross product of any vector with itself is zero $(\vec{B} 	imes \vec{B} = 0)$:$\vec{A} 	imes \vec{B} = 0 - (\vec{C} 	imes \vec{B})$.Using the property $\vec{C} 	imes \vec{B} = -(\vec{B} 	imes \vec{C})$:$\vec{A} 	imes \vec{B} = -(-(\vec{B} 	imes \vec{C})) = \vec{B} 	imes \vec{C}$.Thus,$\vec{A} 	imes \vec{B} = \vec{B} 	imes \vec{C} = \vec{C} 	imes \vec{A}$.

If $\vec{A} + \vec{B} + \vec{C} = 0$,then $\vec{A} \times \vec{B}$ is equal to:

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