If A, B and C are non-empty sets,then (A - B) | vedclass

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(C) The expression $(A - B) \cup (B - A)$ represents the symmetric difference of sets $A$ and $B$,denoted as $A \Delta B$.By definition,$A - B = A \ca

Vedclass · Accepted Answer

$(A \cup B) - (A \cap B)$

Vedclass · Answer

(C) The expression $(A - B) \cup (B - A)$ represents the symmetric difference of sets $A$ and $B$,denoted as $A \Delta B$.By definition,$A - B = A \cap B^c$ and $B - A = B \cap A^c$.Thus,$(A - B) \cup (B - A) = (A \cap B^c) \cup (B \cap A^c)$.Using the distributive law,this simplifies to $(A \cup B) - (A \cap B)$,which contains all elements that are in either $A$ or $B$ but not in both.Therefore,the correct option is $(C)$.

If $A, B$ and $C$ are non-empty sets,then $(A - B) \cup (B - A)$ equals:

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