If x = 3 + i,then x^3 - 3x^2 - 8x + 15 = | vedclass

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(D) Given $x = 3 + i$,we have $x - 3 = i$. Squaring both sides,we get $(x - 3)^2 = i^2$. $x^2 - 6x + 9 = -1$,which simplifies to $x^2 - 6x + 10 = 0$.

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$-15$

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(D) Given $x = 3 + i$,we have $x - 3 = i$. Squaring both sides,we get $(x - 3)^2 = i^2$. $x^2 - 6x + 9 = -1$,which simplifies to $x^2 - 6x + 10 = 0$. Now,we divide the polynomial $x^3 - 3x^2 - 8x + 15$ by $x^2 - 6x + 10$ or express it in terms of $(x^2 - 6x + 10)$. $x^3 - 3x^2 - 8x + 15 = x(x^2 - 6x + 10) + 3(x^2 - 6x + 10) - 15$. Substituting $x^2 - 6x + 10 = 0$,we get $x(0) + 3(0) - 15 = -15$.

If $x = 3 + i$,then $x^3 - 3x^2 - 8x + 15 = $

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