If $|z|=1$ and $z \neq \pm 1$,then all the values of $\frac{z}{1-z^2}$ lie on

The equation $\text{Im}\left( \frac{iz - 2}{z - i} \right) + 1 = 0$,where $z \in \mathbb{C}$ and $z \neq i$,represents a part of a circle having radius equal to

For all $z \in \mathbb{C}$ on the curve $C_1: |z| = 4$,let the locus of the point $w = z + \frac{1}{z}$ be the curve $C_2$. Then:

The equation of any $Circle$ in the complex plane is of the form $z \bar{z} + b \bar{z} + \bar{b} z + c = 0$,where $b \in \mathbb{C}$ and $c \in \mathbb{R}$.

The reflection of the complex number $(3 + 2i)$ in the straight line $z = -i \bar{z}$ is-

If a complex number $z$ satisfies $|z|^2+1=|z^2-1|$,then the locus of $z$ is