If {z_1}, {z_2} in mathbb{C},then text{amp}le | vedclass

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(C) We know that $	ext{amp}\left( \frac{z_1}{z_2} ight) = 	ext{amp}(z_1) - 	ext{amp}(z_2)$.Also,$	ext{amp}(\bar{z}) = -	ext{amp}(z)$.Therefore,

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$	ext{amp}\left( \frac{z_1}{\bar{z}_2} ight)$

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(C) We know that $	ext{amp}\left( \frac{z_1}{z_2} ight) = 	ext{amp}(z_1) - 	ext{amp}(z_2)$.Also,$	ext{amp}(\bar{z}) = -	ext{amp}(z)$.Therefore,$	ext{amp}\left( \frac{z_1}{\bar{z}_2} ight) = 	ext{amp}(z_1) - 	ext{amp}(\bar{z}_2)$.Since $	ext{amp}(\bar{z}_2) = -	ext{amp}(z_2)$,we get $	ext{amp}(z_1) - (-	ext{amp}(z_2)) = 	ext{amp}(z_1) + 	ext{amp}(z_2) = 	ext{amp}(z_1 z_2)$.Comparing this with the given options,option $(C)$ is the correct expression.

If ${z_1}, {z_2} \in \mathbb{C}$,then $\text{amp}\left( \frac{z_1}{\bar{z}_2} \right) = $

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