If $h(x) = \sqrt{4f(x) + 3g(x)}$,$f(1) = 4$,$g(1) = 3$,$f'(1) = 4$,and $g'(1) = 3$,then find $h'(1)$.

  • A
    $\frac{5}{12}$
  • B
    $\frac{5}{2}$
  • C
    $\frac{-5}{12}$
  • D
    $\frac{-12}{7}$

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