If $(1 + x)^n = C_0 + C_1x + C_2x^2 + .......... + C_nx^n$,then $\frac{C_1}{C_0} + \frac{2C_2}{C_1} + \frac{3C_3}{C_2} + .... + \frac{nC_n}{C_{n - 1}} = $
- A$\frac{n(n - 1)}{2}$
- B$\frac{n(n + 2)}{2}$
- C$\frac{n(n + 1)}{2}$
- D$\frac{(n - 1)(n - 2)}{2}$
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View SolutionMatch the expressions in List-$I$ with their values in List-$II$ for the expansion $(1+x+x^2)^n = a_0 + a_1 x + a_2 x^2 + \ldots + a_{2n} x^{2n}$.
List-$I$ List-$II$ $(A)$ $a_0 + a_2 + \ldots + a_{2n}$ $(I)$ $n \cdot 3^{n-1}$ $(B)$ $a_1 + a_3 + \ldots + a_{2n-1}$ $(II)$ $n \cdot 3^n$ $(C)$ $a_1 + 2a_2 + 3a_3 + \ldots + 2n a_{2n}$ $(III)$ $\frac{1}{2}(3^n + 1)$ $(IV)$ $\frac{1}{2}(3^n - 1)$
The correct match is:
| List-$I$ | List-$II$ |
| $(A)$ $a_0 + a_2 + \ldots + a_{2n}$ | $(I)$ $n \cdot 3^{n-1}$ |
| $(B)$ $a_1 + a_3 + \ldots + a_{2n-1}$ | $(II)$ $n \cdot 3^n$ |
| $(C)$ $a_1 + 2a_2 + 3a_3 + \ldots + 2n a_{2n}$ | $(III)$ $\frac{1}{2}(3^n + 1)$ |
| $(IV)$ $\frac{1}{2}(3^n - 1)$ |
The correct match is:
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