If $f(x) = [x]$ for $x \in (-1, 2)$,then $f$ is discontinuous at (where $[x]$ represents the floor function).

  • A
    $x = -1, 0, 1, 2$
  • B
    $x = -1, 0, 1$
  • C
    $x = 0, 1$
  • D
    $x = 2$

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