If p rightarrow (sim p vee sim q) is false,th | vedclass

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(C) The implication $p \rightarrow r$ is false only when $p$ is $T$ and $r$ is $F$. Here,$p \rightarrow (\sim p \vee \sim q)$ is false. This implies $

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$T, T$

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(C) The implication $p \rightarrow r$ is false only when $p$ is $T$ and $r$ is $F$. Here,$p \rightarrow (\sim p \vee \sim q)$ is false. This implies $p = T$ and $(\sim p \vee \sim q) = F$. Since $p = T$,$\sim p = F$. Substituting this,we get $(F \vee \sim q) = F$. For the disjunction to be false,both components must be false. Thus,$\sim q = F$,which means $q = T$. Therefore,the truth values are $p = T$ and $q = T$.

If $p \rightarrow (\sim p \vee \sim q)$ is false,then the truth values of $p$ and $q$ are respectively:

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