If $\vec{a}=\hat{i}-\hat{k}, \vec{b}=x \hat{i}+\hat{j}+(1-x) \hat{k}$ and $\vec{c}=y \hat{i}+x \hat{j}+(1+x-y) \hat{k}$,then $[\vec{a} \vec{b} \vec{c}]$ depends on

  • A
    neither $x$ nor $y$
  • B
    only $x$
  • C
    only $y$
  • D
    both $x$ and $y$

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