If 2x + 3y - 5z = 7,x + y + z = 6,and 3x - 4y | vedclass

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(C) According to Cramer's Rule,for a system of linear equations $a_1x + b_1y + c_1z = d_1$,$a_2x + b_2y + c_2z = d_2$,and $a_3x + b_3y + c_3z = d_3$,t

Vedclass · Accepted Answer

$\left| \begin{array}{ccc} 7 & 3 & -5 \ 6 & 1 & 1 \ 1 & -4 & 2 \end{array} ight| \div \left| \begin{array}{ccc} 2 & 3 & -5 \ 1 & 1 & 1 \ 3 & -4 & 2 \end{array} ight|$

Vedclass · Answer

(C) According to Cramer's Rule,for a system of linear equations $a_1x + b_1y + c_1z = d_1$,$a_2x + b_2y + c_2z = d_2$,and $a_3x + b_3y + c_3z = d_3$,the value of $x$ is given by $x = \frac{D_x}{D}$.Here,$D = \left| \begin{array}{ccc} a_1 & b_1 & c_1 \ a_2 & b_2 & c_2 \ a_3 & b_3 & c_3 \end{array} ight| = \left| \begin{array}{ccc} 2 & 3 & -5 \ 1 & 1 & 1 \ 3 & -4 & 2 \end{array} ight|$.And $D_x$ is obtained by replacing the first column of $D$ with the constants $d_1, d_2, d_3$,so $D_x = \left| \begin{array}{ccc} 7 & 3 & -5 \ 6 & 1 & 1 \ 1 & -4 & 2 \end{array} ight|$.Thus,$x = \frac{D_x}{D} = \left| \begin{array}{ccc} 7 & 3 & -5 \ 6 & 1 & 1 \ 1 & -4 & 2 \end{array} ight| \div \left| \begin{array}{ccc} 2 & 3 & -5 \ 1 & 1 & 1 \ 3 & -4 & 2 \end{array} ight|$.

If $2x + 3y - 5z = 7$,$x + y + z = 6$,and $3x - 4y + 2z = 1$,then $x =$

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