If A = begin{bmatrix} 3 & 1 -1 & 2 end{bmatr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given $A = \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix}$.To find ${A^2}$,we perform matrix multiplication $A 	imes A$:${A^2} = \begin{bmatrix} 3

Vedclass · Accepted Answer

$\begin{bmatrix} 8 & 5 \ -5 & 3 \end{bmatrix}$

Vedclass · Answer

(D) Given $A = \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix}$.To find ${A^2}$,we perform matrix multiplication $A 	imes A$:${A^2} = \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix} \begin{bmatrix} 3 & 1 \ -1 & 2 \end{bmatrix}$Calculating the elements:Row $1$,Column $1$: $(3 	imes 3) + (1 	imes -1) = 9 - 1 = 8$Row $1$,Column $2$: $(3 	imes 1) + (1 	imes 2) = 3 + 2 = 5$Row $2$,Column $1$: $(-1 	imes 3) + (2 	imes -1) = -3 - 2 = -5$Row $2$,Column $2$: $(-1 	imes 1) + (2 	imes 2) = -1 + 4 = 3$Thus,${A^2} = \begin{bmatrix} 8 & 5 \ -5 & 3 \end{bmatrix}$.

If $A = \begin{bmatrix} 3 & 1 \\ -1 & 2 \end{bmatrix}$,then ${A^2} = $

Similar Questions

If $A = \begin{bmatrix} 1 & 0 & 2 \\ 2 & 1 & 3 \\ 3 & 2 & 4 \end{bmatrix}$,then $A^2 - 5A + 6I =$

Let $G(x) = \begin{bmatrix} \cos x & -\sin x & 0 \\ \sin x & \cos x & 0 \\ 0 & 0 & 1 \end{bmatrix}$. If $x+y=0$,then $G(x) G(y) =$

If $A$ and $B$ are two matrices such that $A+B$ and $AB$ are both defined, then

If $A^{\prime}=\begin{bmatrix}-2 & 3 \\ 1 & 2\end{bmatrix}$ and $B=\begin{bmatrix}-1 & 0 \\ 1 & 2\end{bmatrix},$ then find $(A+2B)^{\prime}$.

Express the following matrix as the sum of a symmetric and a skew-symmetric matrix: $\left[\begin{array}{ccc}3 & 3 & -1 \\ -2 & -2 & 1 \\ -4 & -5 & 2\end{array}\right]$

Vedclass Test Series

Exam Paper Generator

Online Exam Module