If A = begin{bmatrix} 4 & 2 -1 & 1 end{bmatr | vedclass

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(B) Given $A = \begin{bmatrix} 4 & 2 \ -1 & 1 \end{bmatrix}$ and $I = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$.First,calculate $(A - 2I)$:$A - 2

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$O$

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(B) Given $A = \begin{bmatrix} 4 & 2 \ -1 & 1 \end{bmatrix}$ and $I = \begin{bmatrix} 1 & 0 \ 0 & 1 \end{bmatrix}$.First,calculate $(A - 2I)$:$A - 2I = \begin{bmatrix} 4 & 2 \ -1 & 1 \end{bmatrix} - \begin{bmatrix} 2 & 0 \ 0 & 2 \end{bmatrix} = \begin{bmatrix} 2 & 2 \ -1 & -1 \end{bmatrix}$.Next,calculate $(A - 3I)$:$A - 3I = \begin{bmatrix} 4 & 2 \ -1 & 1 \end{bmatrix} - \begin{bmatrix} 3 & 0 \ 0 & 3 \end{bmatrix} = \begin{bmatrix} 1 & 2 \ -1 & -2 \end{bmatrix}$.Now,multiply the two matrices:$(A - 2I)(A - 3I) = \begin{bmatrix} 2 & 2 \ -1 & -1 \end{bmatrix} \begin{bmatrix} 1 & 2 \ -1 & -2 \end{bmatrix} = \begin{bmatrix} (2)(1) + (2)(-1) & (2)(2) + (2)(-2) \ (-1)(1) + (-1)(-1) & (-1)(2) + (-1)(-2) \end{bmatrix} = \begin{bmatrix} 0 & 0 \ 0 & 0 \end{bmatrix} = O$.

If $A = \begin{bmatrix} 4 & 2 \\ -1 & 1 \end{bmatrix}$ and $I$ is the identity matrix of order $2$,then $(A - 2I)(A - 3I) = $

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