If $\sin^2 \theta = \frac{1}{4},$ then the most general value of $\theta$ is
- A$2n\pi \pm (-1)^n \frac{\pi}{6}$
- B$\frac{n\pi}{2} \pm (-1)^n \frac{\pi}{6}$
- C$n\pi \pm \frac{\pi}{6}$
- D$2n\pi \pm \frac{\pi}{6}$
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DifficultAP EAMCET 2017
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