If y = (cos x^{2})^{2},then frac{dy}{dx} is e | vedclass

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(C) $y = (\cos x^{2})^{2}$ Differentiating with respect to $x$ using the chain rule: $\frac{dy}{dx} = 2(\cos x^{2}) \cdot \frac{d}{dx}(\cos x^{2})$ $\

Vedclass · Accepted Answer

$-2x \sin 2x^{2}$

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(C) $y = (\cos x^{2})^{2}$ Differentiating with respect to $x$ using the chain rule: $\frac{dy}{dx} = 2(\cos x^{2}) \cdot \frac{d}{dx}(\cos x^{2})$ $\frac{dy}{dx} = 2(\cos x^{2}) \cdot (-\sin x^{2}) \cdot \frac{d}{dx}(x^{2})$ $\frac{dy}{dx} = 2(\cos x^{2}) \cdot (-\sin x^{2}) \cdot (2x)$ $\frac{dy}{dx} = -4x \sin x^{2} \cos x^{2}$ Using the trigonometric identity $\sin 2	heta = 2 \sin 	heta \cos 	heta$,we have: $\frac{dy}{dx} = -2x(2 \sin x^{2} \cos x^{2}) = -2x \sin 2x^{2}$

If $y = (\cos x^{2})^{2}$,then $\frac{dy}{dx}$ is equal to

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