If y=a sin ^3 t and x=a cos ^3 t,then frac{d | vedclass

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(D) Given $y=a \sin ^3 t$ and $x=a \cos ^3 t$. First,differentiate $y$ with respect to $t$: $\frac{d y}{d t} = 3a \sin ^2 t \cos t$. Next,differentiat

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(D) Given $y=a \sin ^3 t$ and $x=a \cos ^3 t$. First,differentiate $y$ with respect to $t$: $\frac{d y}{d t} = 3a \sin ^2 t \cos t$. Next,differentiate $x$ with respect to $t$: $\frac{d x}{d t} = 3a \cos ^2 t (-\sin t) = -3a \cos ^2 t \sin t$. Now,find $\frac{d y}{d x} = \frac{d y / d t}{d x / d t} = \frac{3a \sin ^2 t \cos t}{-3a \cos ^2 t \sin t} = -\frac{\sin t}{\cos t} = -	an t$. At $t = \frac{3 \pi}{4}$,$\frac{d y}{d x} = -	an(\frac{3 \pi}{4}) = -(-1) = 1$.

If $y=a \sin ^3 t$ and $x=a \cos ^3 t$,then $\frac{d y}{d x}$ at $t=\frac{3 \pi}{4}$ is

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