If A + B + C = 180^{circ},then tan A + tan B | vedclass

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(C) Given $A + B + C = 180^{\circ}$,we have $A + B = 180^{\circ} - C$. Taking tangent on both sides: $	an(A + B) = 	an(180^{\circ} - C)$. Using the

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$	an A 	an B 	an C$

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(C) Given $A + B + C = 180^{\circ}$,we have $A + B = 180^{\circ} - C$. Taking tangent on both sides: $	an(A + B) = 	an(180^{\circ} - C)$. Using the formula $	an(A + B) = \frac{	an A + 	an B}{1 - 	an A 	an B}$ and $	an(180^{\circ} - C) = -	an C$,we get: $\frac{	an A + 	an B}{1 - 	an A 	an B} = -	an C$. Multiplying both sides by $(1 - 	an A 	an B)$,we get: $	an A + 	an B = -	an C(1 - 	an A 	an B)$. $	an A + 	an B = -	an C + 	an A 	an B 	an C$. Rearranging the terms,we get: $	an A + 	an B + 	an C = 	an A 	an B 	an C$.

If $A + B + C = 180^{\circ}$,then $\tan A + \tan B + \tan C = $

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