If A is the areal velocity of a planet of mas | vedclass

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(B) The areal velocity $A$ is defined as the rate at which the area is swept by the position vector of the planet.$A = \frac{dA}{dt} = \frac{1}{2} r^2

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$2MA$

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(B) The areal velocity $A$ is defined as the rate at which the area is swept by the position vector of the planet.$A = \frac{dA}{dt} = \frac{1}{2} r^2 \omega$Multiplying both sides by the mass $M$ of the planet:$MA = \frac{1}{2} M r^2 \omega$Since the moment of inertia $I$ of a point mass $M$ at distance $r$ is $I = M r^2$,we have:$MA = \frac{1}{2} I \omega$We know that the angular momentum $L$ is given by $L = I \omega$.Substituting $L$ into the equation:$MA = \frac{1}{2} L$Therefore,the angular momentum $L$ is:$L = 2MA$

If $A$ is the areal velocity of a planet of mass $M$,its angular momentum is

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