If $\sin \left(x+\frac{\pi}{3}\right)+\sin \left(x-\frac{\pi}{3}\right)=1$,then find the value of $x$ in the interval $[0, \pi]$.
- A$\frac{\pi}{2}$
- B$\frac{\pi}{3}$
- C$0$
- D$\frac{\pi}{4}$
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