If $A(2, 3)$ and $B(2, -3)$ are two points,then the equation of the locus of a point $P$ such that $PA + PB = 8$ is

  • A
    $16x^2 + 7y^2 - 64x - 48 = 0$
  • B
    $16x^2 + 7y^2 - 64x + 48 = 0$
  • C
    $16x^2 - 7y^2 + 64x - 48 = 0$
  • D
    $16x^2 - 7y^2 + 64x + 48 = 0$

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At which point on the line $x = 3$ are the tangents drawn to the circle $x^2 + y^2 = 8$ perpendicular to each other?

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