यदि $\frac{x^4}{(x-1)(x-2)(x-3)} = x+k+\frac{A}{x-1}+\frac{B}{x-2}+\frac{C}{x-3}$ है,तो $k+A-B+C=$

  • A
    $104$
  • B
    $52$
  • C
    $63$
  • D
    $\frac{127}{2}$

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Similar Questions

यदि $\frac{x^3}{(2x-1)(x+2)(x-3)}$ का समतुल्य आंशिक भिन्न $A+\frac{B}{2x-1}+\frac{C}{x+2}+\frac{D}{x-3}$ द्वारा दिया गया है,तो $C$ का मान ज्ञात कीजिए।

यदि $\frac{x^3+x^2+1}{(x^2+2)(x^2+3)}=\frac{Ax+B}{x^2+2}+\frac{Cx+D}{x^2+3}$ है,तो $A+B+C+D=$

यदि $\frac{x^2-3x+2}{(x-4)(x-3)^2}=\frac{A}{x-4}+\frac{B}{x-3}+\frac{C}{(x-3)^2}$ है, तो $A+B+C=$

यदि $\frac{2x^2-3x+5}{(x-7)^3}=\frac{A}{x-7}+\frac{B}{(x-7)^2}+\frac{C}{(x-7)^3}$ है, तो $2A-3B+C=$

यदि $\frac{1}{x^4+1}=\frac{A x+B}{x^2+\sqrt{2} x+1}+\frac{C x+D}{x^2-\sqrt{2} x+1}$ है,तो $B D-A C=$

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