If $\int \frac{dx}{x^2+2x+2}=f(x)+c$,then $f(x)$ is equal to :
- A$\tan^{-1}(x+1)$
- B$2 \tan^{-1}(x+1)$
- C$-\tan^{-1}(x+1)$
- D$3 \tan^{-1}(x+1)$
Explore More
Similar Questions
For $x \in \left(\frac{3 \pi}{4}, \pi\right)$, evaluate the integral $\int(\sqrt{1+\sin 2 x}+\sqrt{1-\sin 2 x}) \, dx$.
$\int \frac{1}{9 \cos ^2 x-24 \sin x \cos x+16 \sin ^2 x} d x=$
If $\int \frac{\cos 8 x+1}{\cot 2 x-\tan 2 x} \,d x=A \cos 8 x+c$, where $c$ is an arbitrary constant, then the value of $A$ is
DifficultMHT CET 2023
View SolutionIf $\int \frac{1+\cos (4 x)}{\cot (x)-\tan (x)} d x=k \cos (4 x)+c$,then
DifficultAP EAMCET 2020
View SolutionIf $\int \tan ^4 x dx = a \tan ^3 x + b \tan x + c x + k$ (where $k$ is the constant of integration),then the value of $a - b + c =$
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo