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| List-$I$ | List-$II$ |
| $(i)$ $\overrightarrow{a} \cdot \overrightarrow{b}$ | $(A)$ $\overrightarrow{a} \cdot \overrightarrow{d}$ |
| (ii) $\overrightarrow{b} \cdot \overrightarrow{c}$ | $(B)$ $3$ |
| (iii) $[\overrightarrow{a} \overrightarrow{b} \overrightarrow{c}]$ | $(C)$ $\overrightarrow{b} \cdot \overrightarrow{d}$ |
| (iv) $\overrightarrow{b} \times \overrightarrow{c}$ | $(D)$ $2\hat{i}-2\hat{k}$ |
| $(E)$ $2\hat{j}+2\hat{k}$ | |
| $(F)$ $4$ |
| List $I$ | List $II$ |
| $P$. Volume of parallelepiped determined by vectors $\vec{a}, \vec{b}$ and $\vec{c}$ is $2$. Then the volume of the parallelepiped determined by vectors $2(\vec{a} \times \vec{b}), 3(\vec{b} \times \vec{c})$ and $(\vec{c} \times \vec{a})$ is | $1$. $100$ |
| $Q$. Volume of parallelepiped determined by vectors $\vec{a}, \vec{b}$ and $\vec{c}$ is $5$. Then the volume of the parallelepiped determined by vectors $3(\vec{a}+\vec{b}), (\vec{b}+\vec{c})$ and $2(\vec{c}+\vec{a})$ is | $2$. $30$ |
| $R$. Area of a triangle with adjacent sides determined by vectors $\vec{a}$ and $\vec{b}$ is $20$. Then the area of the triangle with adjacent sides determined by vectors $(2\vec{a}+3\vec{b})$ and $(\vec{a}-\vec{b})$ is | $3$. $24$ |
| $S$. Area of a parallelogram with adjacent sides determined by vectors $\vec{a}$ and $\vec{b}$ is $30$. Then the area of the parallelogram with adjacent sides determined by vectors $(\vec{a}+\vec{b})$ and $\vec{a}$ is | $4$. $60$ |
| Column $I$ | Column $II$ |
| $(A)$ If $\vec{a}=\hat{j}+\sqrt{3} \hat{k}, \vec{b}=-\hat{j}+\sqrt{3} \hat{k}$ and $\vec{c}=2 \sqrt{3} \hat{k}$ form a triangle,then the internal angle of the triangle between $\vec{a}$ and $\vec{b}$ is | $(p)$ $\frac{\pi}{6}$ |
| $(B)$ If $\int_a^b(f(x)-3 x) d x=a^2-b^2$,then the value of $f\left(\frac{\pi}{6}\right)$ is | $(q)$ $\frac{2 \pi}{3}$ |
| $(C)$ The value of $\frac{\pi^2}{\ln 3} \int_{1 / 6}^{5 / 6} \sec (\pi x) d x$ is | $(r)$ $\frac{\pi}{3}$ |
| $(D)$ The maximum value of $|\operatorname{Arg}(\frac{1}{1-z})|$ for $|z|=1, z \neq 1$ is given by | $(s)$ $\pi$ |
| $(t)$ $\frac{\pi}{2}$ |
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