If $Q(\alpha, \beta, \gamma)$ is the harmonic conjugate of the point $P(0, -7, 1)$ with respect to the line segment joining the points $A(2, -5, 3)$ and $B(-1, -8, 0)$,then $\alpha - \beta + \gamma =$

Let $P(\alpha, 4, 7)$ and $Q(3, \beta, 8)$ be two points. If the $YZ$-plane divides the line segment joining $P$ and $Q$ in the ratio $2:3$ and the $ZX$-plane divides the line segment joining $P$ and $Q$ in the ratio $4:5$,then the length of the line segment $PQ$ is:

The point $\left( \frac{1}{2}, -\frac{13}{4} \right)$ divides the line segment joining the points $(3, -5)$ and $(-7, 2)$ in the ratio of:

Given that the points $A(1,0,1), B(2,-1,3)$ and $C(3,-2,5)$ are collinear,then the ratio in which $C$ divides $\overline{AB}$ from the side of $A$ is $...$

Points $A(3, 2, 4)$, $B\left(\frac{33}{5}, \frac{28}{5}, \frac{38}{5}\right)$ and $C(9, 8, 10)$ are given. The ratio in which $B$ divides $\overline{AC}$ is

If $P$ divides the line segment joining the points $A(1, 2, -1)$ and $B(-1, 0, 1)$ externally in the ratio $1: 2$ and $Q = (1, 3, -1)$,then $PQ =$