If $X$ is a random variable such that $P(X=-2)=P(X=-1)=P(X=2)=P(X=1)=\frac{1}{6}$ and $P(X=0)=\frac{1}{3}$,then the mean of $X$ is

  • A
    $\frac{5}{3}$
  • B
    $1$
  • C
    $0$
  • D
    $\frac{3}{5}$

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