If E, M, J and G respectively denote energy,m | vedclass

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(B) The given quantity is $\frac{E J^2}{M^5 G^2}$.We know the dimensional formulas for the given quantities are:$E = [M L^2 T^{-2}]$$J = [M L^2 T^{-1}

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angle

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(B) The given quantity is $\frac{E J^2}{M^5 G^2}$.We know the dimensional formulas for the given quantities are:$E = [M L^2 T^{-2}]$$J = [M L^2 T^{-1}]$$M = [M]$$G = [M^{-1} L^3 T^{-2}]$Substituting these dimensions into the expression:$\frac{[M L^2 T^{-2}] [M L^2 T^{-1}]^2}{[M]^5 [M^{-1} L^3 T^{-2}]^2} = \frac{[M L^2 T^{-2}] [M^2 L^4 T^{-2}]}{[M^5] [M^{-2} L^6 T^{-4}]} = \frac{[M^3 L^6 T^{-4}]}{[M^3 L^6 T^{-4}]} = [M^0 L^0 T^0]$.The resulting quantity is dimensionless.Among the given options,an angle is a dimensionless quantity.

If $E, M, J$ and $G$ respectively denote energy,mass,angular momentum,and universal gravitational constant,the quantity which has the same dimensions as the dimensions of $\frac{E J^2}{M^5 G^2}$ is:

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