If (x-2) is a common factor of the expression | vedclass

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(D) Since $(x-2)$ is a common factor of the expressions $x^2+ax+b$ and $x^2+cx+d$,we have: $2^2 + 2a + b = 0 \Rightarrow 4 + 2a + b = 0$ ... $(i)$ $2^

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$2$

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(D) Since $(x-2)$ is a common factor of the expressions $x^2+ax+b$ and $x^2+cx+d$,we have: $2^2 + 2a + b = 0 \Rightarrow 4 + 2a + b = 0$ ... $(i)$ $2^2 + 2c + d = 0 \Rightarrow 4 + 2c + d = 0$ ... $(ii)$ Subtracting equation $(ii)$ from equation $(i)$: $(4 + 2a + b) - (4 + 2c + d) = 0$ $2a + b - 2c - d = 0$ $b - d = 2c - 2a$ $b - d = 2(c - a)$ Therefore,$\frac{b-d}{c-a} = 2$.

If $(x-2)$ is a common factor of the expressions $x^2+ax+b$ and $x^2+cx+d$,then $\frac{b-d}{c-a}$ is equal to

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