If $1, \omega, \omega^2$ are the cube roots of unity,$n \in \mathbb{N}$ and $n > 2$,then the least value of $n$ such that $1+\omega$ is a root of $x^n-x=0$ is

  • A
    $3$
  • B
    $5$
  • C
    $7$
  • D
    $4$

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