If $1, \omega, \omega^2, \ldots, \omega^8$ are the roots of the equation $x^9-1=0$,then $\sum_{r=1}^8 \left(\omega^r\right)^{99} =$

  • A
    $0$
  • B
    $8$
  • C
    $1$
  • D
    $\omega$

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$\omega$ is a complex cube root of unity. Match the items of List-$I$ to the items of List-$II$.
List-$I$ (Expression)List-$II$ (Value)
$A$. $\omega^{1010} + \omega^{2000}$$I$. $0$
$B$. $(1 + \omega - \omega^2)(1 - \omega + \omega^2)$$II$. $1$
$C$. $(2 + \omega^2 + \omega^4)^5$$III$. $-1$
$D$. $(3 + 5\omega + 3\omega^2)^3$$IV$. $4$
$V$. $8$

The correct match is:

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