If $A(-2, 1)$,$B(0, -2)$,and $C(1, 2)$ are the vertices of a triangle $ABC$,then the perpendicular distance from its circumcentre to the side $BC$ is

  • A
    $\frac{7 \sqrt{13}}{22}$
  • B
    $\frac{3 \sqrt{17}}{22}$
  • C
    $\frac{5 \sqrt{10}}{11}$
  • D
    $\frac{\sqrt{2026}}{22}$

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