If $d = \lambda (a \times b) + \mu (b \times c) + \nu (c \times a)$ and $[a, b, c] = \frac{1}{8}$,then $\lambda + \mu + \nu$ is equal to

  • A
    $8d \cdot (a + b + c)$
  • B
    $8d \times (a + b + c)$
  • C
    $\frac{d}{8} \cdot (a + b + c)$
  • D
    $\frac{d}{8} \times (a + b + c)$

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