If $\theta$ is the angle between the circles $x^2+y^2-4x+2y-4=0$ and $x^2+y^2-2x+4y-11=0$,then $\sin \theta=$

  • A
    $\frac{\sqrt{47}}{24}$
  • B
    $\frac{23}{25}$
  • C
    $\frac{23}{24}$
  • D
    $\frac{\sqrt{3}}{5}$

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