If $l$ is the maximum value of $-3x^2+4x+1$ and $m$ is the minimum value of $3x^2+4x+1$,then the equation of the hyperbola having foci at $(l, 0)$ and $(7m, 0)$ and eccentricity $e=2$ is

  • A
    $36x^2-12y^2=49$
  • B
    $2x^2-5y^2=1$
  • C
    $49x^2-36y^2=12$
  • D
    $36x^2-12y^2=1$

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The eccentricity of the hyperbola conjugate to the hyperbola $\frac{x^2}{4} - \frac{y^2}{12} = 1$ is

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The equation of the normal to the hyperbola $\frac{x^{2}}{16} - \frac{y^{2}}{9} = 1$ at $(-4, 0)$ is

Let $H : \frac{x^2}{a^2} - \frac{y^2}{b^2} = 1$,where $a > b > 0$,be a hyperbola in the $xy$-plane whose conjugate axis $LM$ subtends an angle of $60^{\circ}$ at one of its vertices $N$. Let the area of the triangle $LMN$ be $4\sqrt{3}$.
List-$I$ List-$II$
$P$. The length of the conjugate axis of $H$ is $1$. $8$
$Q$. The eccentricity of $H$ is $2$. $\frac{4}{\sqrt{3}}$
$R$. The distance between the foci of $H$ is $3$. $\frac{2}{\sqrt{3}}$
$S$. The length of the latus rectum of $H$ is $4$. $4$

The correct option is:

Tangents are drawn to the hyperbola $\frac{x^2}{9}-\frac{y^2}{4}=1$,parallel to the straight line $2x-y=1$. The points of contact of the tangents on the hyperbola are:
$(A) \left(\frac{9}{2\sqrt{2}}, \frac{1}{\sqrt{2}}\right)$
$(B) \left(-\frac{9}{2\sqrt{2}}, -\frac{1}{\sqrt{2}}\right)$
$(C) (3\sqrt{3}, -2\sqrt{2})$
$(D) (-3\sqrt{3}, 2\sqrt{2})$

The eccentricity of the hyperbola $5x^2 - 4y^2 + 20x + 8y = 4$ is

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