If $S$ is the focus of the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$ lying on the positive $X$-axis and $P(\theta)$ is a point on the ellipse such that $SP=1$,then $\cos \theta=$

  • A
    $\frac{1}{\sqrt{5}}$
  • B
    $\frac{2}{\sqrt{5}}$
  • C
    $\frac{1}{2}$
  • D
    $\frac{1}{3}$

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