If $\lim _{x \rightarrow 4} \frac{2 x^2+(3+2 a) x+3 a}{x^3-2 x^2-23 x+60}=\frac{11}{9}$,then $\lim _{x \rightarrow a} \frac{x^2+9 x+20}{x^2-x-20}=$

  • A
    $-9$
  • B
    $-4$
  • C
    $-\frac{1}{4}$
  • D
    $-\frac{1}{9}$

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